“is” operation returns false even though two objects have same id The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) The Ask Question Wizard is Live! Data science time! April 2019 and salary with experienceHow to return multiple values from a function?Does Python have a ternary conditional operator?Relationship between SciPy and NumPyCreating a singleton in PythonPython: two objects are the sameWhy is [] faster than list()?Why does “not(True) in [False, True]” return False?is comparison returns False with strings using same idHow can two Python objects have same id but 'is' operator returns False?Comparing Objects - Why is == returning 'False' in the following example?

How to read αἱμύλιος or when to aspirate

Did the new image of black hole confirm the general theory of relativity?

Make it rain characters

Would an alien lifeform be able to achieve space travel if lacking in vision?

Didn't get enough time to take a Coding Test - what to do now?

Button changing its text & action. Good or terrible?

What can I do if neighbor is blocking my solar panels intentionally?

Do warforged have souls?

Working through the single responsibility principle (SRP) in Python when calls are expensive

How to handle characters who are more educated than the author?

how can a perfect fourth interval be considered either consonant or dissonant?

The following signatures were invalid: EXPKEYSIG 1397BC53640DB551

How to support a colleague who finds meetings extremely tiring?

What do I do when my TA workload is more than expected?

Can we generate random numbers using irrational numbers like π and e?

What was the last x86 CPU that did not have the x87 floating-point unit built in?

60's-70's movie: home appliances revolting against the owners

Was credit for the black hole image misappropriated?

Voltage transmission

Pretty sure I'm over complicating my loops but unsure how to simplify

different output for groups and groups USERNAME after adding a username to a group

How did passengers keep warm on sail ships?

What aspect of planet earth must be changed to prevent the industrial revolution?

Nested ellipses in tikzpicture: Chomsky hierarchy



“is” operation returns false even though two objects have same id



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
The Ask Question Wizard is Live!
Data science time! April 2019 and salary with experienceHow to return multiple values from a function?Does Python have a ternary conditional operator?Relationship between SciPy and NumPyCreating a singleton in PythonPython: two objects are the sameWhy is [] faster than list()?Why does “not(True) in [False, True]” return False?is comparison returns False with strings using same idHow can two Python objects have same id but 'is' operator returns False?Comparing Objects - Why is == returning 'False' in the following example?



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








8















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question



















  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    2 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    2 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    2 hours ago






  • 1





    References aren't shared between two variables; each variable is a reference to the object it refers to.

    – chepner
    1 hour ago






  • 1





    @C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

    – juanpa.arrivillaga
    1 hour ago

















8















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question



















  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    2 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    2 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    2 hours ago






  • 1





    References aren't shared between two variables; each variable is a reference to the object it refers to.

    – chepner
    1 hour ago






  • 1





    @C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

    – juanpa.arrivillaga
    1 hour ago













8












8








8








Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!










share|improve this question
















Two python objects have the same id but "is" operation returns false as shown below:



a = np.arange(12).reshape(2, -1)
c = a.reshape(12, 1)
print("id(c.data)", id(c.data))
print("id(a.data)", id(a.data))

print(c.data is a.data)
print(id(c.data) == id(a.data))


Here is the actual output:



id(c.data) 241233112
id(a.data) 241233112
False
True


My question is... why "c.data is a.data" returns false even though they point to the same ID, thus pointing to the same object? I thought that they point to the same object if they have same ID or am I wrong? Thank you!







python numpy






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 hours ago









ribitskiyb

376




376










asked 2 hours ago









drminixdrminix

513




513







  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    2 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    2 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    2 hours ago






  • 1





    References aren't shared between two variables; each variable is a reference to the object it refers to.

    – chepner
    1 hour ago






  • 1





    @C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

    – juanpa.arrivillaga
    1 hour ago












  • 1





    @C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

    – chepner
    2 hours ago






  • 2





    @C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

    – chepner
    2 hours ago






  • 1





    @C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

    – juanpa.arrivillaga
    2 hours ago






  • 1





    References aren't shared between two variables; each variable is a reference to the object it refers to.

    – chepner
    1 hour ago






  • 1





    @C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

    – juanpa.arrivillaga
    1 hour ago







1




1





@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

– chepner
2 hours ago





@C.Nivs They don't even necessarily have different memory addresses (something which Python doesn't expose). Whatever memory was used for the first may have been reused for the second.

– chepner
2 hours ago




2




2





@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

– chepner
2 hours ago





@C.Nivs Don't think of it in terms of memory addresses. How memory is managed is completely implementation dependent. All you know for sure is that two objects that overlap in time will not have the same id.

– chepner
2 hours ago




1




1





@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

– juanpa.arrivillaga
2 hours ago





@C.Nivs no, ids do not belong to variables. They belong to objects. Many variables can reference the same object.

– juanpa.arrivillaga
2 hours ago




1




1





References aren't shared between two variables; each variable is a reference to the object it refers to.

– chepner
1 hour ago





References aren't shared between two variables; each variable is a reference to the object it refers to.

– chepner
1 hour ago




1




1





@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

– juanpa.arrivillaga
1 hour ago





@C.Nivs yes, you need to understand, Python variables are not like C variables. The best way is to think of a Python variable as literally a key in a dict. This is actually true for the global scope, but modern python optimizes local scopes as essentially arrays/symbol tables. In any case, just as you can have 100 references to the same object in a dict, a variable can reference the same object, or a different object, and the ID belongs to the object, not the variable.

– juanpa.arrivillaga
1 hour ago












2 Answers
2






active

oldest

votes


















11














a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



In the second if statement, each object is released as soon as id returns its id.



If you save references to both objects, keeping them alive, you can see they are not the same object.



r0 = a.data
r1 = c.data
assert r0 is not r1





share|improve this answer




















  • 2





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    2 hours ago











  • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    2 hours ago











  • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    2 hours ago






  • 3





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    2 hours ago


















3














In [62]: a = np.arange(12).reshape(2,-1) 
...: c = a.reshape(12,1)


.data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



In [63]: a.data 
Out[63]: <memory at 0x7f672d1101f8>
In [64]: c.data
Out[64]: <memory at 0x7f672d1103a8>
In [65]: type(a.data)
Out[65]: memoryview


https://docs.python.org/3/library/stdtypes.html#memoryview



If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



In [66]: a.__array_interface__['data'] 
Out[66]: (50988640, False)
In [67]: c.__array_interface__['data']
Out[67]: (50988640, False)


It even shows the offset produced by slicing - here 24 bytes, 3*8



In [68]: c[3:].__array_interface__['data'] 
Out[68]: (50988664, False)



I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
In [71]: d
Out[71]:
array([[ 0, 1, 2, 3, 4, 5],
[ 6, 7, 8, 9, 10, 11]])
In [72]: d.__array_interface__['data']
Out[72]: (50988640, False)


But normally we create new arrays with shared memory with slicing or np.array (copy=False).






share|improve this answer

























    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55658189%2fis-operation-returns-false-even-though-two-objects-have-same-id%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    11














    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer




















    • 2





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      2 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      2 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      2 hours ago






    • 3





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      2 hours ago















    11














    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer




















    • 2





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      2 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      2 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      2 hours ago






    • 3





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      2 hours ago













    11












    11








    11







    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1





    share|improve this answer















    a.data and c.data both produce a transient object, with no reference to it. As such, both are immediately garbage-collected. The same id can be used for both.



    In your first if statement, the objects have to co-exist while is checks if they are identical, which they are not.



    In the second if statement, each object is released as soon as id returns its id.



    If you save references to both objects, keeping them alive, you can see they are not the same object.



    r0 = a.data
    r1 = c.data
    assert r0 is not r1






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 hours ago

























    answered 2 hours ago









    chepnerchepner

    262k35251345




    262k35251345







    • 2





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      2 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      2 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      2 hours ago






    • 3





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      2 hours ago












    • 2





      what is confusing is the fact that data looks like an attribute, but is probably a property

      – Jean-François Fabre
      2 hours ago











    • In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

      – amanb
      2 hours ago











    • @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

      – C.Nivs
      2 hours ago






    • 3





      a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

      – Jean-François Fabre
      2 hours ago







    2




    2





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    2 hours ago





    what is confusing is the fact that data looks like an attribute, but is probably a property

    – Jean-François Fabre
    2 hours ago













    In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    2 hours ago





    In my tests, the id's are different in the first run, but change to become the same on subsequent runs.

    – amanb
    2 hours ago













    @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    2 hours ago





    @Jean-FrançoisFabre so would that mean that the object itself is only returned when a getter is called, and the property is not actually stored in the class? I'm not quite familiar with the differences between a property vs attribute

    – C.Nivs
    2 hours ago




    3




    3





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    2 hours ago





    a property is a method disguised as an attribute. So it can return a discardable integer, object, whatever.

    – Jean-François Fabre
    2 hours ago













    3














    In [62]: a = np.arange(12).reshape(2,-1) 
    ...: c = a.reshape(12,1)


    .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



    In [63]: a.data 
    Out[63]: <memory at 0x7f672d1101f8>
    In [64]: c.data
    Out[64]: <memory at 0x7f672d1103a8>
    In [65]: type(a.data)
    Out[65]: memoryview


    https://docs.python.org/3/library/stdtypes.html#memoryview



    If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



    In [66]: a.__array_interface__['data'] 
    Out[66]: (50988640, False)
    In [67]: c.__array_interface__['data']
    Out[67]: (50988640, False)


    It even shows the offset produced by slicing - here 24 bytes, 3*8



    In [68]: c[3:].__array_interface__['data'] 
    Out[68]: (50988664, False)



    I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



    In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
    In [71]: d
    Out[71]:
    array([[ 0, 1, 2, 3, 4, 5],
    [ 6, 7, 8, 9, 10, 11]])
    In [72]: d.__array_interface__['data']
    Out[72]: (50988640, False)


    But normally we create new arrays with shared memory with slicing or np.array (copy=False).






    share|improve this answer





























      3














      In [62]: a = np.arange(12).reshape(2,-1) 
      ...: c = a.reshape(12,1)


      .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



      In [63]: a.data 
      Out[63]: <memory at 0x7f672d1101f8>
      In [64]: c.data
      Out[64]: <memory at 0x7f672d1103a8>
      In [65]: type(a.data)
      Out[65]: memoryview


      https://docs.python.org/3/library/stdtypes.html#memoryview



      If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



      In [66]: a.__array_interface__['data'] 
      Out[66]: (50988640, False)
      In [67]: c.__array_interface__['data']
      Out[67]: (50988640, False)


      It even shows the offset produced by slicing - here 24 bytes, 3*8



      In [68]: c[3:].__array_interface__['data'] 
      Out[68]: (50988664, False)



      I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



      In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
      In [71]: d
      Out[71]:
      array([[ 0, 1, 2, 3, 4, 5],
      [ 6, 7, 8, 9, 10, 11]])
      In [72]: d.__array_interface__['data']
      Out[72]: (50988640, False)


      But normally we create new arrays with shared memory with slicing or np.array (copy=False).






      share|improve this answer



























        3












        3








        3







        In [62]: a = np.arange(12).reshape(2,-1) 
        ...: c = a.reshape(12,1)


        .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



        In [63]: a.data 
        Out[63]: <memory at 0x7f672d1101f8>
        In [64]: c.data
        Out[64]: <memory at 0x7f672d1103a8>
        In [65]: type(a.data)
        Out[65]: memoryview


        https://docs.python.org/3/library/stdtypes.html#memoryview



        If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



        In [66]: a.__array_interface__['data'] 
        Out[66]: (50988640, False)
        In [67]: c.__array_interface__['data']
        Out[67]: (50988640, False)


        It even shows the offset produced by slicing - here 24 bytes, 3*8



        In [68]: c[3:].__array_interface__['data'] 
        Out[68]: (50988664, False)



        I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



        In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
        In [71]: d
        Out[71]:
        array([[ 0, 1, 2, 3, 4, 5],
        [ 6, 7, 8, 9, 10, 11]])
        In [72]: d.__array_interface__['data']
        Out[72]: (50988640, False)


        But normally we create new arrays with shared memory with slicing or np.array (copy=False).






        share|improve this answer















        In [62]: a = np.arange(12).reshape(2,-1) 
        ...: c = a.reshape(12,1)


        .data returns a memoryview object. id just gives the id of that object; it's not the value of the object, or any indication of where a databuffer is located.



        In [63]: a.data 
        Out[63]: <memory at 0x7f672d1101f8>
        In [64]: c.data
        Out[64]: <memory at 0x7f672d1103a8>
        In [65]: type(a.data)
        Out[65]: memoryview


        https://docs.python.org/3/library/stdtypes.html#memoryview



        If you want to verify that a and c share a data buffer, I find the __array_interface__ to be a better tool.



        In [66]: a.__array_interface__['data'] 
        Out[66]: (50988640, False)
        In [67]: c.__array_interface__['data']
        Out[67]: (50988640, False)


        It even shows the offset produced by slicing - here 24 bytes, 3*8



        In [68]: c[3:].__array_interface__['data'] 
        Out[68]: (50988664, False)



        I haven't seen much use of a.data. It can be used as the buffer object when creating a new array with ndarray:



        In [70]: d = np.ndarray((2,6), dtype=a.dtype, buffer=a.data) 
        In [71]: d
        Out[71]:
        array([[ 0, 1, 2, 3, 4, 5],
        [ 6, 7, 8, 9, 10, 11]])
        In [72]: d.__array_interface__['data']
        Out[72]: (50988640, False)


        But normally we create new arrays with shared memory with slicing or np.array (copy=False).







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 2 hours ago

























        answered 2 hours ago









        hpauljhpaulj

        118k787160




        118k787160



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55658189%2fis-operation-returns-false-even-though-two-objects-have-same-id%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Isurus Índice Especies | Notas | Véxase tamén | Menú de navegación"A compendium of fossil marine animal genera (Chondrichthyes entry)"o orixinal"A review of the Tertiary fossil Cetacea (Mammalia) localities in wales port taf Museum Victoria"o orixinalThe Vertebrate Fauna of the Selma Formation of Alabama. Part VII. Part VIII. The Mosasaurs The Fishes50419737IDsh85068767Isurus2548834613242066569678159923NHMSYS00210535017845105743

            Is 1 ppb equal to 1 μg/kg? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How to determine the concentration after a dilution with Beer's law?What would be SMILES notation for a compound with delocalized bonding?Amount of substance of a molecule in a solute the same as amount of substance of constituent elements?Interpreting notation format 1.64E-02 from particulate emission dataWhat was the lithium concentration in 1940's 7-Up?Why are osmoles not considered SI units?Why is Ka constant when volume is increased?Should residual sodium be considered in measuring sodium content of sweat?Concentration of mercury in bodyConversion from a PPB value to µg/m3 of Isobutylene

            What does “fit” mean in this sentence? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)How does 'jealousy' mean 'suspicion'?What does “not so say” mean?Does “somebody of my caliber” mean the speaker themselves?“accounting for high fasting blood glucose”- help about the meaningWhat does “cloaked by NDA” mean in this context?What does it mean by 'community ownership' in this context?What does “human corroborators” mean in this context?What does “everything but a fire” mean in this context?What does “run” mean here?What does “rabbited” mean/imply in this sentence?