Compilation of a 2d array and a 1d array The Next CEO of Stack OverflowInserting points along a linear interval between adjacent coordinates in an arrayDynamic arrays and lists with compile (Append, Linked lists etc.)Numbering indices / array element positions while creating an array (using 3 argument form)Lattice model array for distribution of energyinsert elements into 2 D arraySpeed differences between Table, Replace, Array, Map, and AssociationMapUsing a set of indices to select a subset of an array2D array summation operationsEfficiency in array element replacementSelect an element from each matrix row/column specified by a vector

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Compilation of a 2d array and a 1d array

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Compilation of a 2d array and a 1d array



The Next CEO of Stack OverflowInserting points along a linear interval between adjacent coordinates in an arrayDynamic arrays and lists with compile (Append, Linked lists etc.)Numbering indices / array element positions while creating an array (using 3 argument form)Lattice model array for distribution of energyinsert elements into 2 D arraySpeed differences between Table, Replace, Array, Map, and AssociationMapUsing a set of indices to select a subset of an array2D array summation operationsEfficiency in array element replacementSelect an element from each matrix row/column specified by a vector










2












$begingroup$


With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…










share|improve this question









$endgroup$
















    2












    $begingroup$


    With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…










    share|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…










      share|improve this question









      $endgroup$




      With a list say x1,y1,x2,y2… and a list z1, what is the best way to create a list x1,y1,z1,x2,y2,z1,x3,y3,z1…







      list-manipulation array






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 3 hours ago









      tombom21tombom21

      133




      133




















          2 Answers
          2






          active

          oldest

          votes


















          4












          $begingroup$

          You can use PadRight:



          PadRight[
          x1, y1, x2, y2,
          Automatic, 3,
          z1
          ]



          x1, y1, z1, x2, y2, z1




          Or ArrayPad:



          ArrayPad[
          x1, y1, x2, y2, x3, y3,
          0,0,0,1,
          z1
          ]



          x1, y1, z1, x2, y2, z1, x3, y3, z1







          share|improve this answer









          $endgroup$




















            1












            $begingroup$

            n = 1000000;
            a = RandomReal[-1, 1, n, 2];
            b = ConstantArray[0., 1];
            c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



            0.016







            share|improve this answer









            $endgroup$













              Your Answer





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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              4












              $begingroup$

              You can use PadRight:



              PadRight[
              x1, y1, x2, y2,
              Automatic, 3,
              z1
              ]



              x1, y1, z1, x2, y2, z1




              Or ArrayPad:



              ArrayPad[
              x1, y1, x2, y2, x3, y3,
              0,0,0,1,
              z1
              ]



              x1, y1, z1, x2, y2, z1, x3, y3, z1







              share|improve this answer









              $endgroup$

















                4












                $begingroup$

                You can use PadRight:



                PadRight[
                x1, y1, x2, y2,
                Automatic, 3,
                z1
                ]



                x1, y1, z1, x2, y2, z1




                Or ArrayPad:



                ArrayPad[
                x1, y1, x2, y2, x3, y3,
                0,0,0,1,
                z1
                ]



                x1, y1, z1, x2, y2, z1, x3, y3, z1







                share|improve this answer









                $endgroup$















                  4












                  4








                  4





                  $begingroup$

                  You can use PadRight:



                  PadRight[
                  x1, y1, x2, y2,
                  Automatic, 3,
                  z1
                  ]



                  x1, y1, z1, x2, y2, z1




                  Or ArrayPad:



                  ArrayPad[
                  x1, y1, x2, y2, x3, y3,
                  0,0,0,1,
                  z1
                  ]



                  x1, y1, z1, x2, y2, z1, x3, y3, z1







                  share|improve this answer









                  $endgroup$



                  You can use PadRight:



                  PadRight[
                  x1, y1, x2, y2,
                  Automatic, 3,
                  z1
                  ]



                  x1, y1, z1, x2, y2, z1




                  Or ArrayPad:



                  ArrayPad[
                  x1, y1, x2, y2, x3, y3,
                  0,0,0,1,
                  z1
                  ]



                  x1, y1, z1, x2, y2, z1, x3, y3, z1








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 3 hours ago









                  Carl WollCarl Woll

                  72.2k395186




                  72.2k395186





















                      1












                      $begingroup$

                      n = 1000000;
                      a = RandomReal[-1, 1, n, 2];
                      b = ConstantArray[0., 1];
                      c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                      0.016







                      share|improve this answer









                      $endgroup$

















                        1












                        $begingroup$

                        n = 1000000;
                        a = RandomReal[-1, 1, n, 2];
                        b = ConstantArray[0., 1];
                        c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                        0.016







                        share|improve this answer









                        $endgroup$















                          1












                          1








                          1





                          $begingroup$

                          n = 1000000;
                          a = RandomReal[-1, 1, n, 2];
                          b = ConstantArray[0., 1];
                          c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                          0.016







                          share|improve this answer









                          $endgroup$



                          n = 1000000;
                          a = RandomReal[-1, 1, n, 2];
                          b = ConstantArray[0., 1];
                          c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                          0.016








                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 3 hours ago









                          Henrik SchumacherHenrik Schumacher

                          58.7k581162




                          58.7k581162



























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