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Escape a backup date in a file name

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Escape a backup date in a file name

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3

I have been trying to:

cp file.csv file.$(date +%D).csv

But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.

And I have been trying again to:

cp file.csv file.$(printf "%q" $(date +%D)).csv

But it still fails.

shell filenames date escape-characters slash

share|improve this question

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
  
  – tres.14159
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
  
  – 0xSheepdog
  12 hours ago
  
  

  
  
  
  

add a comment | 

3

I have been trying to:

cp file.csv file.$(date +%D).csv

But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.

And I have been trying again to:

cp file.csv file.$(printf "%q" $(date +%D)).csv

But it still fails.

shell filenames date escape-characters slash

share|improve this question

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can not set a filename with slash characters: stackoverflow.com/questions/9847288/…
  
  – tres.14159
  12 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  the problem is your use of the date format using the / character. You said it yourself, the shell is seeing them as directory markers. Try one of the many other options available from date. You might be able to get the / escaped so the filename uses the character code (like putting a space in a filename), but that is often problematic.
  
  – 0xSheepdog
  12 hours ago
  
  

  
  
  
  

add a comment | 

I have been trying to:

cp file.csv file.$(date +%D).csv

But it fails because the filenames is: file.03/27/19.csv with the slash of separate directories.

And I have been trying again to:

cp file.csv file.$(printf "%q" $(date +%D)).csv

But it still fails.

shell filenames date escape-characters slash

share|improve this question

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

cp file.csv file.$(date +%D).csv

cp file.csv file.$(printf "%q" $(date +%D)).csv

share|improve this question

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

share|improve this question

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

edited 7 hours ago

Gilles

544k12811041621

edited 7 hours ago

Gilles

544k12811041621

asked 12 hours ago

tres.14159tres.14159

2814

asked 12 hours ago

tres.14159tres.14159

2814

1 Answer
1

active

oldest

votes

14

You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.

You can use characters that look like / like ⁄ (fraction slash), so you could do:

 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"

But you may run into problems like the file name being rendered differently in locales using a different charset.

My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3^rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):

 cp file.csv "file.$(date +%Y-%m-%d).csv"

Which with many date implementations you can shorten to:

 cp file.csv "file.$(date +%F).csv"

share|improve this answer

edited 11 hours ago

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

add a comment | 

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14

You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.

You can use characters that look like / like ⁄ (fraction slash), so you could do:

 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"

But you may run into problems like the file name being rendered differently in locales using a different charset.

My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3^rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):

 cp file.csv "file.$(date +%Y-%m-%d).csv"

Which with many date implementations you can shorten to:

 cp file.csv "file.$(date +%F).csv"

share|improve this answer

edited 11 hours ago

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

add a comment | 

14

You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.

You can use characters that look like / like ⁄ (fraction slash), so you could do:

 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"

But you may run into problems like the file name being rendered differently in locales using a different charset.

My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3^rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):

 cp file.csv "file.$(date +%Y-%m-%d).csv"

Which with many date implementations you can shorten to:

 cp file.csv "file.$(date +%F).csv"

share|improve this answer

edited 11 hours ago

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

add a comment | 

You can't have / (byte 0x2F on ASCII-based systems) in a file name, period.

You can use characters that look like / like ⁄ (fraction slash), so you could do:

 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"

But you may run into problems like the file name being rendered differently in locales using a different charset.

My advice would be to use the standard non-ambiguous (for most people outside the US, 03/12/18 would be interpreted as the 3^rd of December 2018 for instance) YYYY-mm-dd format instead (which also helps wrt sorting):

 cp file.csv "file.$(date +%Y-%m-%d).csv"

Which with many date implementations you can shorten to:

 cp file.csv "file.$(date +%F).csv"

share|improve this answer

edited 11 hours ago

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

 cp file.csv "file.$(date +%D | sed 's|/|⁄|g').csv"

 cp file.csv "file.$(date +%Y-%m-%d).csv"

 cp file.csv "file.$(date +%F).csv"

share|improve this answer

edited 11 hours ago

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946

answered 12 hours ago

Stéphane ChazelasStéphane Chazelas

312k57589946