(Soft question) does light intensity oscillate really fast since it is a wave?Question about the wave nature of lightIntensity of light wave penetrating soft tissueHow does light oscillate?Doesn't light have to be a wave since it has a wave length? (In contrast to the wave–particle duality)How does distance affect light intensity?What does “intensity of light” mean?Why does the intensity of light decrease as you move away from a particular point (described in question)?Relationship between intensity and amplitude of light waveFeynman’s Treatment of an Opaque Wallwhy does the intensity of light does not vary with time in youngs double slit experiment

Information to fellow intern about hiring?

Why is the design of haulage companies so “special”?

Extreme, but not acceptable situation and I can't start the work tomorrow morning

How is it possible for user's password to be changed after storage was encrypted? (on OS X, Android)

Email Account under attack (really) - anything I can do?

What do the Banks children have against barley water?

Could a US political party gain complete control over the government by removing checks & balances?

Are cabin dividers used to "hide" the flex of the airplane?

Map list to bin numbers

Shall I use personal or official e-mail account when registering to external websites for work purpose?

(Soft question) does light intensity oscillate really fast since it is a wave?

"My colleague's body is amazing"

How to make payment on the internet without leaving a money trail?

What is the command to reset a PC without deleting any files

Copycat chess is back

Landing in very high winds

Is a vector space a subspace of itself?

Landlord wants to switch my lease to a "Land contract" to "get back at the city"

Why was the "bread communication" in the arena of Catching Fire left out in the movie?

What does 'script /dev/null' do?

I’m planning on buying a laser printer but concerned about the life cycle of toner in the machine

Can one use the reaction spell from the War Caster feat to cast Bigby's Hand?

Can I find out the caloric content of bread by dehydrating it?

Calculate Levenshtein distance between two strings in Python



(Soft question) does light intensity oscillate really fast since it is a wave?


Question about the wave nature of lightIntensity of light wave penetrating soft tissueHow does light oscillate?Doesn't light have to be a wave since it has a wave length? (In contrast to the wave–particle duality)How does distance affect light intensity?What does “intensity of light” mean?Why does the intensity of light decrease as you move away from a particular point (described in question)?Relationship between intensity and amplitude of light waveFeynman’s Treatment of an Opaque Wallwhy does the intensity of light does not vary with time in youngs double slit experiment













2












$begingroup$


If you shine light on a wall, what will be seen is a "patch" with constant intensity. However, if light is viewed as a wave, then it is oscillations of the electromagnetic field changing from 0 to the amplitude and back really fast. So my question is, if I were able to look at the world at extreme slow motion, a quadrillion times slower or so, and I shined a beam of light at a wall, will I see a "patch" with oscillating intensity, with maximum brightness at the peaks of the wave and minimum when the field is 0? If so, is the constant brightness seen normally just our puny mortal eyes capturing only the average of this oscillating brightness?










share|cite|improve this question







New contributor




Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    2












    $begingroup$


    If you shine light on a wall, what will be seen is a "patch" with constant intensity. However, if light is viewed as a wave, then it is oscillations of the electromagnetic field changing from 0 to the amplitude and back really fast. So my question is, if I were able to look at the world at extreme slow motion, a quadrillion times slower or so, and I shined a beam of light at a wall, will I see a "patch" with oscillating intensity, with maximum brightness at the peaks of the wave and minimum when the field is 0? If so, is the constant brightness seen normally just our puny mortal eyes capturing only the average of this oscillating brightness?










    share|cite|improve this question







    New contributor




    Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      2












      2








      2





      $begingroup$


      If you shine light on a wall, what will be seen is a "patch" with constant intensity. However, if light is viewed as a wave, then it is oscillations of the electromagnetic field changing from 0 to the amplitude and back really fast. So my question is, if I were able to look at the world at extreme slow motion, a quadrillion times slower or so, and I shined a beam of light at a wall, will I see a "patch" with oscillating intensity, with maximum brightness at the peaks of the wave and minimum when the field is 0? If so, is the constant brightness seen normally just our puny mortal eyes capturing only the average of this oscillating brightness?










      share|cite|improve this question







      New contributor




      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      If you shine light on a wall, what will be seen is a "patch" with constant intensity. However, if light is viewed as a wave, then it is oscillations of the electromagnetic field changing from 0 to the amplitude and back really fast. So my question is, if I were able to look at the world at extreme slow motion, a quadrillion times slower or so, and I shined a beam of light at a wall, will I see a "patch" with oscillating intensity, with maximum brightness at the peaks of the wave and minimum when the field is 0? If so, is the constant brightness seen normally just our puny mortal eyes capturing only the average of this oscillating brightness?







      visible-light waves electromagnetic-radiation intensity






      share|cite|improve this question







      New contributor




      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







      New contributor




      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question






      New contributor




      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 31 mins ago









      AdgornAdgorn

      113




      113




      New contributor




      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Adgorn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          3 Answers
          3






          active

          oldest

          votes


















          2












          $begingroup$

          In a plane polarized EMW the electric and the magnetic fields are phase-shifted like $sin(omega t)$ and $cos(omega t)$, and the light intensity is a sum of squares, so you get a constant intensity$ Ipropto E^2+B^2= textconst$.



          However, some devices are much more sensitive to the electric field than to the magnetic one (photo effect, for example), so they "feel" oscillations.



          There are also some devices (magnetic antennas, for example) that are more sensitive to the magnetic field (some radio-receivers).






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
            $endgroup$
            – EL_DON
            1 min ago



















          1












          $begingroup$

          You would need a coherent beam, because in waves it is not only intensity but also phase that makes a difference. In an incoherent beam, as sunlight, you would not get any changes in this thought experiment, because the average intensity would hold even at wavelength distances.



          In a coherent laser beam you should see in your thought experiment what is shown towards the end of this youtube video, the sinusoidal pattern of impinging intensity . After all, mathematics allows us to materialize thought experiments as this one.






          share|cite|improve this answer









          $endgroup$




















            0












            $begingroup$

            The EM field strength in a light wave does indeed cross through zero in between + and - peaks, just like the surface of a pond goes through its natural rest height in between going up and down as ripples go by. If you slowed the wave down, you'd change its frequency, which is the same as changing its color. You could change from blue, to red, to infrared, and all the way through radio waves and other invisible colors. So no, you could not see the EM field changing as a flashing light for a slow wave (the slow changes couldn't simulate your vision receptors) , but you could set up an electric field meter and measure the change in field as the (no longer visible) wave went by. What does it really mean for the field to cross through zero? Not much; just like having the surface of a pond cross through its equilibrium height doesn't mean the ripples are gone, neither does a moment of 0 electric field mean the light wave is gone.






            share|cite|improve this answer









            $endgroup$













              Your Answer





              StackExchange.ifUsing("editor", function ()
              return StackExchange.using("mathjaxEditing", function ()
              StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
              StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
              );
              );
              , "mathjax-editing");

              StackExchange.ready(function()
              var channelOptions =
              tags: "".split(" "),
              id: "151"
              ;
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function()
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled)
              StackExchange.using("snippets", function()
              createEditor();
              );

              else
              createEditor();

              );

              function createEditor()
              StackExchange.prepareEditor(
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: false,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: null,
              bindNavPrevention: true,
              postfix: "",
              imageUploader:
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              ,
              noCode: true, onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              );



              );






              Adgorn is a new contributor. Be nice, and check out our Code of Conduct.









              draft saved

              draft discarded


















              StackExchange.ready(
              function ()
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f471463%2fsoft-question-does-light-intensity-oscillate-really-fast-since-it-is-a-wave%23new-answer', 'question_page');

              );

              Post as a guest















              Required, but never shown

























              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2












              $begingroup$

              In a plane polarized EMW the electric and the magnetic fields are phase-shifted like $sin(omega t)$ and $cos(omega t)$, and the light intensity is a sum of squares, so you get a constant intensity$ Ipropto E^2+B^2= textconst$.



              However, some devices are much more sensitive to the electric field than to the magnetic one (photo effect, for example), so they "feel" oscillations.



              There are also some devices (magnetic antennas, for example) that are more sensitive to the magnetic field (some radio-receivers).






              share|cite|improve this answer









              $endgroup$












              • $begingroup$
                I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
                $endgroup$
                – EL_DON
                1 min ago
















              2












              $begingroup$

              In a plane polarized EMW the electric and the magnetic fields are phase-shifted like $sin(omega t)$ and $cos(omega t)$, and the light intensity is a sum of squares, so you get a constant intensity$ Ipropto E^2+B^2= textconst$.



              However, some devices are much more sensitive to the electric field than to the magnetic one (photo effect, for example), so they "feel" oscillations.



              There are also some devices (magnetic antennas, for example) that are more sensitive to the magnetic field (some radio-receivers).






              share|cite|improve this answer









              $endgroup$












              • $begingroup$
                I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
                $endgroup$
                – EL_DON
                1 min ago














              2












              2








              2





              $begingroup$

              In a plane polarized EMW the electric and the magnetic fields are phase-shifted like $sin(omega t)$ and $cos(omega t)$, and the light intensity is a sum of squares, so you get a constant intensity$ Ipropto E^2+B^2= textconst$.



              However, some devices are much more sensitive to the electric field than to the magnetic one (photo effect, for example), so they "feel" oscillations.



              There are also some devices (magnetic antennas, for example) that are more sensitive to the magnetic field (some radio-receivers).






              share|cite|improve this answer









              $endgroup$



              In a plane polarized EMW the electric and the magnetic fields are phase-shifted like $sin(omega t)$ and $cos(omega t)$, and the light intensity is a sum of squares, so you get a constant intensity$ Ipropto E^2+B^2= textconst$.



              However, some devices are much more sensitive to the electric field than to the magnetic one (photo effect, for example), so they "feel" oscillations.



              There are also some devices (magnetic antennas, for example) that are more sensitive to the magnetic field (some radio-receivers).







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered 20 mins ago









              Vladimir KalitvianskiVladimir Kalitvianski

              11.2k11334




              11.2k11334











              • $begingroup$
                I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
                $endgroup$
                – EL_DON
                1 min ago

















              • $begingroup$
                I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
                $endgroup$
                – EL_DON
                1 min ago
















              $begingroup$
              I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
              $endgroup$
              – EL_DON
              1 min ago





              $begingroup$
              I've heard this before, but I don't see how you satisfy Maxwell's equations with it. $nablatimes E=-partial B/partial t$ doesn't work if $Epropto cos(omega t-kcdot x)$ unless $B$ is also a cosine because they each take one derivative. Also, the poynting vector goes like $Etimes B$, so you'd get periodic variation in energy flux, anyway.
              $endgroup$
              – EL_DON
              1 min ago












              1












              $begingroup$

              You would need a coherent beam, because in waves it is not only intensity but also phase that makes a difference. In an incoherent beam, as sunlight, you would not get any changes in this thought experiment, because the average intensity would hold even at wavelength distances.



              In a coherent laser beam you should see in your thought experiment what is shown towards the end of this youtube video, the sinusoidal pattern of impinging intensity . After all, mathematics allows us to materialize thought experiments as this one.






              share|cite|improve this answer









              $endgroup$

















                1












                $begingroup$

                You would need a coherent beam, because in waves it is not only intensity but also phase that makes a difference. In an incoherent beam, as sunlight, you would not get any changes in this thought experiment, because the average intensity would hold even at wavelength distances.



                In a coherent laser beam you should see in your thought experiment what is shown towards the end of this youtube video, the sinusoidal pattern of impinging intensity . After all, mathematics allows us to materialize thought experiments as this one.






                share|cite|improve this answer









                $endgroup$















                  1












                  1








                  1





                  $begingroup$

                  You would need a coherent beam, because in waves it is not only intensity but also phase that makes a difference. In an incoherent beam, as sunlight, you would not get any changes in this thought experiment, because the average intensity would hold even at wavelength distances.



                  In a coherent laser beam you should see in your thought experiment what is shown towards the end of this youtube video, the sinusoidal pattern of impinging intensity . After all, mathematics allows us to materialize thought experiments as this one.






                  share|cite|improve this answer









                  $endgroup$



                  You would need a coherent beam, because in waves it is not only intensity but also phase that makes a difference. In an incoherent beam, as sunlight, you would not get any changes in this thought experiment, because the average intensity would hold even at wavelength distances.



                  In a coherent laser beam you should see in your thought experiment what is shown towards the end of this youtube video, the sinusoidal pattern of impinging intensity . After all, mathematics allows us to materialize thought experiments as this one.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 21 mins ago









                  anna vanna v

                  161k8153453




                  161k8153453





















                      0












                      $begingroup$

                      The EM field strength in a light wave does indeed cross through zero in between + and - peaks, just like the surface of a pond goes through its natural rest height in between going up and down as ripples go by. If you slowed the wave down, you'd change its frequency, which is the same as changing its color. You could change from blue, to red, to infrared, and all the way through radio waves and other invisible colors. So no, you could not see the EM field changing as a flashing light for a slow wave (the slow changes couldn't simulate your vision receptors) , but you could set up an electric field meter and measure the change in field as the (no longer visible) wave went by. What does it really mean for the field to cross through zero? Not much; just like having the surface of a pond cross through its equilibrium height doesn't mean the ripples are gone, neither does a moment of 0 electric field mean the light wave is gone.






                      share|cite|improve this answer









                      $endgroup$

















                        0












                        $begingroup$

                        The EM field strength in a light wave does indeed cross through zero in between + and - peaks, just like the surface of a pond goes through its natural rest height in between going up and down as ripples go by. If you slowed the wave down, you'd change its frequency, which is the same as changing its color. You could change from blue, to red, to infrared, and all the way through radio waves and other invisible colors. So no, you could not see the EM field changing as a flashing light for a slow wave (the slow changes couldn't simulate your vision receptors) , but you could set up an electric field meter and measure the change in field as the (no longer visible) wave went by. What does it really mean for the field to cross through zero? Not much; just like having the surface of a pond cross through its equilibrium height doesn't mean the ripples are gone, neither does a moment of 0 electric field mean the light wave is gone.






                        share|cite|improve this answer









                        $endgroup$















                          0












                          0








                          0





                          $begingroup$

                          The EM field strength in a light wave does indeed cross through zero in between + and - peaks, just like the surface of a pond goes through its natural rest height in between going up and down as ripples go by. If you slowed the wave down, you'd change its frequency, which is the same as changing its color. You could change from blue, to red, to infrared, and all the way through radio waves and other invisible colors. So no, you could not see the EM field changing as a flashing light for a slow wave (the slow changes couldn't simulate your vision receptors) , but you could set up an electric field meter and measure the change in field as the (no longer visible) wave went by. What does it really mean for the field to cross through zero? Not much; just like having the surface of a pond cross through its equilibrium height doesn't mean the ripples are gone, neither does a moment of 0 electric field mean the light wave is gone.






                          share|cite|improve this answer









                          $endgroup$



                          The EM field strength in a light wave does indeed cross through zero in between + and - peaks, just like the surface of a pond goes through its natural rest height in between going up and down as ripples go by. If you slowed the wave down, you'd change its frequency, which is the same as changing its color. You could change from blue, to red, to infrared, and all the way through radio waves and other invisible colors. So no, you could not see the EM field changing as a flashing light for a slow wave (the slow changes couldn't simulate your vision receptors) , but you could set up an electric field meter and measure the change in field as the (no longer visible) wave went by. What does it really mean for the field to cross through zero? Not much; just like having the surface of a pond cross through its equilibrium height doesn't mean the ripples are gone, neither does a moment of 0 electric field mean the light wave is gone.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 11 mins ago









                          EL_DONEL_DON

                          2,3142726




                          2,3142726




















                              Adgorn is a new contributor. Be nice, and check out our Code of Conduct.









                              draft saved

                              draft discarded


















                              Adgorn is a new contributor. Be nice, and check out our Code of Conduct.












                              Adgorn is a new contributor. Be nice, and check out our Code of Conduct.











                              Adgorn is a new contributor. Be nice, and check out our Code of Conduct.














                              Thanks for contributing an answer to Physics Stack Exchange!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid


                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.

                              Use MathJax to format equations. MathJax reference.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function ()
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f471463%2fsoft-question-does-light-intensity-oscillate-really-fast-since-it-is-a-wave%23new-answer', 'question_page');

                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              Popular posts from this blog

                              Isurus Índice Especies | Notas | Véxase tamén | Menú de navegación"A compendium of fossil marine animal genera (Chondrichthyes entry)"o orixinal"A review of the Tertiary fossil Cetacea (Mammalia) localities in wales port taf Museum Victoria"o orixinalThe Vertebrate Fauna of the Selma Formation of Alabama. Part VII. Part VIII. The Mosasaurs The Fishes50419737IDsh85068767Isurus2548834613242066569678159923NHMSYS00210535017845105743

                              Wolfenstein 3D Contents Availability Essential improvements Game data Video settings Input settings Audio settings Network VR support Issues fixed Other information System requirements NotesReferences    3D Realms Wolfenstein 3D pageGOG.com Community DiscussionsGOG.com Support PageSteam Community DiscussionsWolfenstein WikiOfficial websiteAmazon.comBethesda.netGamersGateGOG.comGreen Man GamingHumble StoreSteamweb browser versionWolfenstein 3D: Super UpgradesherehereUltraWolfhereWolfMenuECWolf Wolf4SDL WolfGL WinWolf3d NewWolf BetterWolf Sprite Fix and Rotation Project    Wolfenstein 3D VRSplitWolfWolfenstein 3D VRWolfenstein 3D VRWolfenstein 3D VR4DOS command shellFreeDOS's MORE.COMMacBin themthis shim fileWine regeditRELEASE: QUAKE II + III, WOLFENSTEIN 3D, RETURN TO CASTLE WOLFENSTEIN - GOG.com NewsMac Family - Wolfenstein Wiki - WikiaNerdly Pleasures: How many FPS? - DOS Games and Framerates

                              Король Коль Исторические данные | Стихотворение | Примечания | Навигацияверсии1 правкаверсии1 правкаA New interpretation of the 'Artognou' stone, TintagelTintagel IslandАрхивировано