One-one communication Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?The Security to the Party [Part 29]The punctual worker and the stingy bossFinding Doctor NoN people, N hat colors, and a One-Way GlassAnother village of liars and truth-tellersThe Riddle Of SomeYoung man RandolphMeasure the height of my neighbor's buildingNumber of Ways to Make the PathsCommunicating Information about Cards
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One-one communication
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?The Security to the Party [Part 29]The punctual worker and the stingy bossFinding Doctor NoN people, N hat colors, and a One-Way GlassAnother village of liars and truth-tellersThe Riddle Of SomeYoung man RandolphMeasure the height of my neighbor's buildingNumber of Ways to Make the PathsCommunicating Information about Cards
$begingroup$
5 people are standing in a circle - person A needs to tell his salary to person B, but none of the others should know A's salary.
How is this possible, if every person only whispers to the person on the right and B does not stand to the immediate right of A?
riddle mathematics
edited 2 hours ago
JonMark Perry
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
5 people are standing in a circle - person A needs to tell his salary to person B, but none of the others should know A's salary.
How is this possible, if every person only whispers to the person on the right and B does not stand to the immediate right of A?
riddle mathematics
edited 2 hours ago
JonMark Perry
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago
add a comment |
$begingroup$
5 people are standing in a circle - person A needs to tell his salary to person B, but none of the others should know A's salary.
How is this possible, if every person only whispers to the person on the right and B does not stand to the immediate right of A?
riddle mathematics
edited 2 hours ago
JonMark Perry
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
5 people are standing in a circle - person A needs to tell his salary to person B, but none of the others should know A's salary.
How is this possible, if every person only whispers to the person on the right and B does not stand to the immediate right of A?
riddle mathematics
riddle mathematics
edited 2 hours ago
JonMark Perry
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
JonMark Perry
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
JonMark Perry
20.8k64199
edited 2 hours ago
JonMark Perry
20.8k64199
edited 2 hours ago
JonMark Perry
20.8k64199
20.8k64199
asked 3 hours ago
aceace
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago
aceace
262
asked 3 hours ago
aceace
262
262
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ace is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago
add a comment |
1
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago
1
1
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
B sits on the left of A. A asks for B's salary and B whispers his/her salary to A. Then A whispers
his own salary+B's salarycounter-clockwise. When B hears what A whispered to others, A tells him/her to substract his/her own salary from it.
answered 21 mins ago
btwbtw
1286
$endgroup$
add a comment |
$begingroup$
The most simple answer (but it can be unsuitable):
A and B can use public-key cryptography (e.g. with Diffie-Hellman key exchange). The problem becomes even easier because the message (the salary) to send is a number. So, all the messages being whispered will be in the form "Tell A(B) the number 50694, please".
answered 3 hours ago
trolley813trolley813
1,16638
$endgroup$
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
add a comment |
$begingroup$
I will speculate here a bit. Given that everybody passes exactly what he/she got and does not change anything.
If A knows B's salary, then he can just pass something like it is 700 more than yours
If A and B could communicate before the game started, then they could figure out some function to determine it and pass the numbers. For example: $F(x,y) = x^y + y*x$. So saying 14 and 3 would mean $14^3 + 14*3 = 2744 + 42 = 2786$
They could also use some coder/decoder to pass it if they both know the algorithm that's being used
answered 2 hours ago
NovargNovarg
3,4171229
$endgroup$
add a comment |
$begingroup$
How about this:
A whispers a random number, when it gets to B, then B adds a different random number and whispers along the circle. When it gets back to A, calculate the difference between the number sent and the number received. Now A can whisper the sum of A's salary and the secret number.
So the people on one side of A know number x.
The people on the other side of A know number z = x + y but neither x nor y.
The people on the fist side of A know z + s without knowing either z or s.
Only A and B know all of x, y and s (where s is the secret salary).
answered 31 mins ago
JayJay
2,6692921
$endgroup$
add a comment |
$begingroup$
B starts the conversation with his own salary. When it gets to A, A says A+B. When this gets back to B, B now knows A's salary.
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
$endgroup$
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
B sits on the left of A. A asks for B's salary and B whispers his/her salary to A. Then A whispers
his own salary+B's salarycounter-clockwise. When B hears what A whispered to others, A tells him/her to substract his/her own salary from it.
answered 21 mins ago
btwbtw
1286
$endgroup$
add a comment |
$begingroup$
B sits on the left of A. A asks for B's salary and B whispers his/her salary to A. Then A whispers
his own salary+B's salarycounter-clockwise. When B hears what A whispered to others, A tells him/her to substract his/her own salary from it.
answered 21 mins ago
btwbtw
1286
$endgroup$
add a comment |
$begingroup$
B sits on the left of A. A asks for B's salary and B whispers his/her salary to A. Then A whispers
his own salary+B's salarycounter-clockwise. When B hears what A whispered to others, A tells him/her to substract his/her own salary from it.
answered 21 mins ago
btwbtw
1286
$endgroup$
B sits on the left of A. A asks for B's salary and B whispers his/her salary to A. Then A whispers
his own salary+B's salarycounter-clockwise. When B hears what A whispered to others, A tells him/her to substract his/her own salary from it.
answered 21 mins ago
btwbtw
1286
edited 15 mins ago
answered 21 mins ago
btwbtw
1286
answered 21 mins ago
btwbtw
1286
answered 21 mins ago
btwbtw
1286
1286
add a comment |
add a comment |
$begingroup$
The most simple answer (but it can be unsuitable):
A and B can use public-key cryptography (e.g. with Diffie-Hellman key exchange). The problem becomes even easier because the message (the salary) to send is a number. So, all the messages being whispered will be in the form "Tell A(B) the number 50694, please".
answered 3 hours ago
trolley813trolley813
1,16638
$endgroup$
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
add a comment |
$begingroup$
The most simple answer (but it can be unsuitable):
A and B can use public-key cryptography (e.g. with Diffie-Hellman key exchange). The problem becomes even easier because the message (the salary) to send is a number. So, all the messages being whispered will be in the form "Tell A(B) the number 50694, please".
answered 3 hours ago
trolley813trolley813
1,16638
$endgroup$
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
add a comment |
$begingroup$
The most simple answer (but it can be unsuitable):
A and B can use public-key cryptography (e.g. with Diffie-Hellman key exchange). The problem becomes even easier because the message (the salary) to send is a number. So, all the messages being whispered will be in the form "Tell A(B) the number 50694, please".
answered 3 hours ago
trolley813trolley813
1,16638
$endgroup$
The most simple answer (but it can be unsuitable):
A and B can use public-key cryptography (e.g. with Diffie-Hellman key exchange). The problem becomes even easier because the message (the salary) to send is a number. So, all the messages being whispered will be in the form "Tell A(B) the number 50694, please".
answered 3 hours ago
trolley813trolley813
1,16638
answered 3 hours ago
trolley813trolley813
1,16638
answered 3 hours ago
trolley813trolley813
1,16638
answered 3 hours ago
trolley813trolley813
1,16638
1,16638
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
add a comment |
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
$begingroup$
Good solution. But I was looking for more of an addition-subtraction based solution, if any.
$endgroup$
– ace
2 hours ago
add a comment |
$begingroup$
I will speculate here a bit. Given that everybody passes exactly what he/she got and does not change anything.
If A knows B's salary, then he can just pass something like it is 700 more than yours
If A and B could communicate before the game started, then they could figure out some function to determine it and pass the numbers. For example: $F(x,y) = x^y + y*x$. So saying 14 and 3 would mean $14^3 + 14*3 = 2744 + 42 = 2786$
They could also use some coder/decoder to pass it if they both know the algorithm that's being used
answered 2 hours ago
NovargNovarg
3,4171229
$endgroup$
add a comment |
$begingroup$
I will speculate here a bit. Given that everybody passes exactly what he/she got and does not change anything.
If A knows B's salary, then he can just pass something like it is 700 more than yours
If A and B could communicate before the game started, then they could figure out some function to determine it and pass the numbers. For example: $F(x,y) = x^y + y*x$. So saying 14 and 3 would mean $14^3 + 14*3 = 2744 + 42 = 2786$
They could also use some coder/decoder to pass it if they both know the algorithm that's being used
answered 2 hours ago
NovargNovarg
3,4171229
$endgroup$
add a comment |
$begingroup$
I will speculate here a bit. Given that everybody passes exactly what he/she got and does not change anything.
If A knows B's salary, then he can just pass something like it is 700 more than yours
If A and B could communicate before the game started, then they could figure out some function to determine it and pass the numbers. For example: $F(x,y) = x^y + y*x$. So saying 14 and 3 would mean $14^3 + 14*3 = 2744 + 42 = 2786$
They could also use some coder/decoder to pass it if they both know the algorithm that's being used
answered 2 hours ago
NovargNovarg
3,4171229
$endgroup$
I will speculate here a bit. Given that everybody passes exactly what he/she got and does not change anything.
If A knows B's salary, then he can just pass something like it is 700 more than yours
If A and B could communicate before the game started, then they could figure out some function to determine it and pass the numbers. For example: $F(x,y) = x^y + y*x$. So saying 14 and 3 would mean $14^3 + 14*3 = 2744 + 42 = 2786$
They could also use some coder/decoder to pass it if they both know the algorithm that's being used
answered 2 hours ago
NovargNovarg
3,4171229
answered 2 hours ago
NovargNovarg
3,4171229
answered 2 hours ago
NovargNovarg
3,4171229
answered 2 hours ago
NovargNovarg
3,4171229
3,4171229
add a comment |
add a comment |
$begingroup$
How about this:
A whispers a random number, when it gets to B, then B adds a different random number and whispers along the circle. When it gets back to A, calculate the difference between the number sent and the number received. Now A can whisper the sum of A's salary and the secret number.
So the people on one side of A know number x.
The people on the other side of A know number z = x + y but neither x nor y.
The people on the fist side of A know z + s without knowing either z or s.
Only A and B know all of x, y and s (where s is the secret salary).
answered 31 mins ago
JayJay
2,6692921
$endgroup$
add a comment |
$begingroup$
How about this:
A whispers a random number, when it gets to B, then B adds a different random number and whispers along the circle. When it gets back to A, calculate the difference between the number sent and the number received. Now A can whisper the sum of A's salary and the secret number.
So the people on one side of A know number x.
The people on the other side of A know number z = x + y but neither x nor y.
The people on the fist side of A know z + s without knowing either z or s.
Only A and B know all of x, y and s (where s is the secret salary).
answered 31 mins ago
JayJay
2,6692921
$endgroup$
add a comment |
$begingroup$
How about this:
A whispers a random number, when it gets to B, then B adds a different random number and whispers along the circle. When it gets back to A, calculate the difference between the number sent and the number received. Now A can whisper the sum of A's salary and the secret number.
So the people on one side of A know number x.
The people on the other side of A know number z = x + y but neither x nor y.
The people on the fist side of A know z + s without knowing either z or s.
Only A and B know all of x, y and s (where s is the secret salary).
answered 31 mins ago
JayJay
2,6692921
$endgroup$
How about this:
A whispers a random number, when it gets to B, then B adds a different random number and whispers along the circle. When it gets back to A, calculate the difference between the number sent and the number received. Now A can whisper the sum of A's salary and the secret number.
So the people on one side of A know number x.
The people on the other side of A know number z = x + y but neither x nor y.
The people on the fist side of A know z + s without knowing either z or s.
Only A and B know all of x, y and s (where s is the secret salary).
answered 31 mins ago
JayJay
2,6692921
answered 31 mins ago
JayJay
2,6692921
answered 31 mins ago
JayJay
2,6692921
answered 31 mins ago
JayJay
2,6692921
2,6692921
add a comment |
add a comment |
$begingroup$
B starts the conversation with his own salary. When it gets to A, A says A+B. When this gets back to B, B now knows A's salary.
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
$endgroup$
add a comment |
$begingroup$
B starts the conversation with his own salary. When it gets to A, A says A+B. When this gets back to B, B now knows A's salary.
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
$endgroup$
add a comment |
$begingroup$
B starts the conversation with his own salary. When it gets to A, A says A+B. When this gets back to B, B now knows A's salary.
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
$endgroup$
B starts the conversation with his own salary. When it gets to A, A says A+B. When this gets back to B, B now knows A's salary.
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
answered 1 min ago
JonMark PerryJonMark Perry
20.8k64199
20.8k64199
add a comment |
add a comment |
ace is a new contributor. Be nice, and check out our Code of Conduct.
ace is a new contributor. Be nice, and check out our Code of Conduct.
ace is a new contributor. Be nice, and check out our Code of Conduct.
ace is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
It can be possible if $B$ stands on the right from $A$ :) So, please clarify the puzzle.
$endgroup$
– trolley813
3 hours ago
$begingroup$
Thank you for pointing that I have edited the puzzle accordingly
$endgroup$
– ace
3 hours ago